How to Calculate Boiler Efficiency Loss (Heat Loss) due to Evaporation of Moisture in the Fuel?
Boiler efficiency loss due to evaporation of moisture present in biomass fuel refers to the energy lost when the moisture in the fuel is evaporated during combustion, resulting in a reduction of the boiler’s thermal efficiency.
To calculate boiler efficiency loss (heat loss) due to evaporation of moisture in the fuel, we use the following formula:
Heat Loss = M × [584 + Cp × (Tf – Ta)] x 100 / GCV
Where:
M = Moisture content in fuel (as a decimal, e.g., 20% = 0.20)
Cp = Specific heat capacity of water vapor (approximately 0.45 kcal/kg·°C)
Tf = Flue gas temperature (°C)
Ta = Ambient temperature (°C)
GCV = Gross Calorific Value of fuel (kcal/kg)
Given Values (for example):
M = 0.20
Cp = 0.45 kcal/kg·°C
Tf = 145°C
Ta = 30°C
GCV = 3900 kcal/kg
Latent heat of vaporization of water (constant) = 584 kcal/kg
Calculation:
Heat Loss = M × [584 + Cp × (Tf – Ta)] x 100 / GCV
= 0.20 × [584 + 0.45 × (145 – 30)] x 100 / 3900
= 0.20 × [584 + 0.45 × 115] x 100 / 3900
= 0.20 × [584 + 51.75] x 100 / 3900
= 0.20 × 635.75 x 100 / 3900
= 12715 / 3900
= 3.26%
Final Answer:
The boiler efficiency loss (heat loss) due to evaporation of moisture in the fuel is approximately 3.26%.
Frequently Asked Questions
1. What is specific heat capacity (Cp)?
Specific heat capacity (Cp) is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 degree Celsius (or Kelvin).
2. What is the Cp value for water vapor?
The Cp value for water vapor is approximately 0.45 kcal/kg°C (or 1.88 kJ/kg°C).
3. Why is Cp important?
Cp is important because it helps calculate the energy required to heat or cool a substance, which is crucial in various engineering and thermodynamic applications.
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